[Java]讀取XML

簡單說明這Code，讀取一個XML檔，並取到每個BBB裡面的每個標籤值

以下為XML檔：



<?xml version="1.0" encoding="UTF-8" ?>
<AAA>
<BBB>
<A>a1</A>
<B>b1</B>
<C>c1</C>
<D>d1</D>
</BBB>
<BBB>
<A>a2</A>
<B>b2</B>
<C>c2</C>
<D>d2</D>
</BBB>
</AAA>



以下為Java Code：

import javax.xml.xpath.*;
import org.w3c.dom.NodeList;
import org.xml.sax.InputSource;
public class TestXML {
 public static void main(String[] args) throws XPathExpressionException {
  XPath xpath = XPathFactory.newInstance().newXPath();
  InputSource inputSource = new InputSource("D:/test.xml");
  NodeList nodes = (NodeList) xpath.evaluate("/AAA/BBB", inputSource, XPathConstants.NODESET);
  for (int i = 0; i < nodes.getLength(); i++) {
   String a = xpath.evaluate("A", nodes.item(i));
   String b = xpath.evaluate("B", nodes.item(i));
   String c = xpath.evaluate("C", nodes.item(i));
   String d = xpath.evaluate("D", nodes.item(i));
   System.out.println("a="+a+"b="+b+"c="+c+"d="+d);
  }
 }
}